(3x+2)(4x^2-19x-5)=0

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Solution for (3x+2)(4x^2-19x-5)=0 equation: 


Simplifying
(3x + 2)(4x2 + -19x + -5) = 0

Reorder the terms:
(2 + 3x)(4x2 + -19x + -5) = 0

Reorder the terms:
(2 + 3x)(-5 + -19x + 4x2) = 0

Multiply (2 + 3x) * (-5 + -19x + 4x2)
(2(-5 + -19x + 4x2) + 3x * (-5 + -19x + 4x2)) = 0
((-5 * 2 + -19x * 2 + 4x2 * 2) + 3x * (-5 + -19x + 4x2)) = 0
((-10 + -38x + 8x2) + 3x * (-5 + -19x + 4x2)) = 0
(-10 + -38x + 8x2 + (-5 * 3x + -19x * 3x + 4x2 * 3x)) = 0
(-10 + -38x + 8x2 + (-15x + -57x2 + 12x3)) = 0

Reorder the terms:
(-10 + -38x + -15x + 8x2 + -57x2 + 12x3) = 0

Combine like terms: -38x + -15x = -53x
(-10 + -53x + 8x2 + -57x2 + 12x3) = 0

Combine like terms: 8x2 + -57x2 = -49x2
(-10 + -53x + -49x2 + 12x3) = 0

Solving
-10 + -53x + -49x2 + 12x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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